Measuring angles: Operations with angles. | |
First two years of secondary education. | |
Adding angles using the sexagesimal measure. |
|
Both time and angles are measured using the
sexagesimal measure. Lets look at the following problem: Luis is a marathon runner who ran a marathon two
days running as part of his training. He found the following: on the first day
he ran the marathon in 2 h 48' 35''; and on the second day he ran it in 2 h 45'
30''. How long did Luis run for in total over the two days. If we add up the hours, minutes and seconds separately
we get the following:
2h 48' 35"
+ 2h 45' 30"
4h 93' 65"
But 65 seconds is equal to
one minute (60 seconds) and 5 seconds, so we could write the total as follows:
4h 94' 5"
Likewise, 94' is equal to one hour and 34 minutes. Therefore,
the total is:
5h 34' 5"
We use the same process to add up the size of angles.
| |
4.
Add the following angles together in your exercise book:
a. 56º 20' 40"
+ 37º 42' 15"
b. 125º 15'
30" + 24º 50' 40"
c. 33º 33' 33"
+ 17º 43' 34"
| |
Use the following window to
construct the angles and check your results.
d1, m1 and s1
correspond to the
degrees, minutes and seconds of the first angle being added and d2, m2 and s2
correspond to those of the second angle being added. |
Subtracting angles using the sexagesimal measure. |
|
In the first race Luis'
friend ran the marathon in exactly 3 hours. What is the difference between
their two times?
We need to carry out the following operation:
3h 0' 0"
- 2h 48' 35"
As
with adding times, we need to subtract the hours, minutes and seconds
separately. However, as we can't take 35 or 48 away from 0 we have to change one
hour into 60 minutes and one minute into 60 seconds. Therefore, 3 hours is
transformed into 2h 59' 60''.
2h 59' 60"
- 2h 48' 35"
0h 11' 25"
| |
5. Subtract the angles from the exercise above in your exercise book:
a. 56º 20' 40"
- 37º 42' 15"
b. 125º 15'
30" - 24º 50' 40"
c. 33º 33' 33"
- 17º 43' 34"
| |
Use this window to construct
these angles and check your results.
d1, m1
and s1 correspond to the degrees, minutes and seconds of the first angle in the operation and d2, m2 and s2
correspond to those of the second angle being subtracted from the first one.
|
Multiplying an angle by a natural number. |
|
In order to multiply
an angle by a natural number we need to multiply each of the parts of the
angle separately (degrees, minutes and seconds). If any of the products of
second or minutes is greater than 60 we change it into one unit of the next
bigger part.
18º 26' 35"
* 3
54º 78' 105"
But 105" = 1' 45", so
54º 79' 45"
But 79' = 1º 19', so
55º 19' 45"
| |
6. Work out the following products:
a. 56º 20'
40" * 2
b. 37º 42' 15" * 4
c. 125º 15'
30" * 2
d. 24º 50' 40" * 3
e. 33º 33' 33" * 3
f. 17º 43' 34" * 2
| |
Put the values for these angles and products into the following window and check your results for the exercise above. |
Dividing an angle by a natural number. | |
In order to divide an angle by a natural number we need to divide the degrees by this number. Then we change the remainder into minutes, by multiplying by 60, and we add this number to the minutes we already have. We then divide the minutes. Then we change the remainder into seconds, by multiplying by 60, and we add this number to the seconds we already have. We then divide the seconds. | |
7. Divide the following angles by the natural
numbers given:
a. 56º 20'
40" : 5
b. 37º 42' 15" : 4
c. 125º 15'
30" : 5
d. 25º 50' 40" : 6
e. 33º 33' 33" : 2
f. 17º 43' 34" * 2
| |
Put the values for these angles and divisors into the following window and check your results for the exercise above. |
Fernando Arias Fernández-Pérez | ||
Spanish Ministry of Education. Year 2001 | ||
Except where otherwise noted, this work is licensed under a Creative Common License