Continuity of functions: Definitions. |
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2nd year of post-compulsory secondary education. | |
Definitions. | ||
We have said that the function y = f(x) is continuous at point a, if f is defined at this point (f(a) exists) then the limit of this function exists when x tends to a, and this limit is the same as f(a). The following definitions are equivalent to this one and are more frequently used:
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10.- Look carefully at the function. Bring P closer to A by dragging it with the mouse or by choosing values for the parameter (a+h) which are close to (a). You can see that h tends to 0 to both the left and right of a. What are the values of the increment of the function f(a+h) - f(a)? Explain your answer. 11.- If we call (a+h) = x , when (x) tends to (a) what does f(x) tend to? Explain your answer. |
Interpreting the continuity of a function at a set point by looking at its graph. | |
We saw earlier that a function, y = f(x), is continuous at point a of the domain if. Using the definition of the limit of a function at a set point we can say that: "For any neighbourhood where f(a) is the centre and ß the radius, there is a neighbourhood with centre a and radius ð so that all its x points have their image, f(x), inside the neighbourhood with centre f(a) and radius ß". In other words: "If x is less than ð away from a, its image f(x) is less than ß away from f(a)".
In the following window we are going to look at this in more detail and focus on the continuity of the function y=x2/10 at the point a=6. | |
f(6) = 3.6 If ß = 1, the P points whose x-coordinate is located within the neighbourhood (6-ð , 6+ð ) = (5,22 , 6,78) has its image f(x) inside the neighbourhood with centre f(6) = 3.6 and radius 1. Check that this is true by dragging P over the curve with the mouse. You can see that as x approaches 6 its image f(x) approaches f(6). Change the value of the parameter ß in the window. You will see that for each value of ß, ð has a different value. Drag P with the mouse and look carefully at the values of x when its image is located in the interval (f(6)-ß, f(6)+ß) . | |
For any value we choose for parameter ß, we always get a value for radius ð, so that if x is less than ð away from 6, then f(x) is less than ß away from f(6) = 3.6 . This means that | |
Let's continue working with the point a = 6. 12.- What is the value of the radius ð if ß = 0.8? 13.- For which values for x is the image f(x) less than 0.5 away from 3.6? You can find the answer by dragging P with the mouse over the curve. Write down your answer. 14.- In your exercise book work out the value of ð depending on ß when a = 6. Is the function continuous at the point x = 6? Change parameter a to see the continuity of the function at other points on the graph in the window. Select a = 5 and answer the following questions: 15.- For which values of x is its image is less than 2 away from f(5)? 16.- When a = 5, does a ð exist for each value of ß ? Work it out and write the answer in your exercise book. Is the function continuous at the point x = 5? |
Belén Pérez Zurdo. | ||
Spanish Ministry of Education. Year 2001 | ||